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0=-0.6x^2+2.7x+7
We move all terms to the left:
0-(-0.6x^2+2.7x+7)=0
We add all the numbers together, and all the variables
-(-0.6x^2+2.7x+7)=0
We get rid of parentheses
0.6x^2-2.7x-7=0
a = 0.6; b = -2.7; c = -7;
Δ = b2-4ac
Δ = -2.72-4·0.6·(-7)
Δ = 24.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.7)-\sqrt{24.09}}{2*0.6}=\frac{2.7-\sqrt{24.09}}{1.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.7)+\sqrt{24.09}}{2*0.6}=\frac{2.7+\sqrt{24.09}}{1.2} $
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